The car must be travelling at a speed of 28.21 m / s in order to land 90 m from the base of a 50 m high cliff.
According to Equations of motion,
s = ut + 1 / 2 at²
s = Distance
u = Initial velocity
t = Time
a = Acceleration
In vertical motion,
s = 50 m
u = 0
a = 9.8 m / s²
50 = 0 + 1 / 2 * 9.8 * t²
t² = 50 / 4.9
t² = 10.2
t = 3.19 s
In horizontal motion,
s = 90 m
a = 0
90 = 3.19 u + 0
u = 90 / 3.19
u = 28.21 m / s
Therefore, the initial speed of the car must be 28.21 m / s
To know more about Equations of motion
https://brainly.com/question/5955789
#SPJ1