The coefficient of kinetic friction is calculated from the values that have been given in the question to be 0.58.
We define the kinetic friction as the friction that acts between two bodies that are moving over each other. Thus it acts when a body tends to slide over another body as we have seen.
We know that;
v^2 = u^2 + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance covered
v^2 - u^2 = 2as
μmg = ma
a = μ/g
μ = (12.1)^2/249.3
μ = 0.58
Learn more about kinetic friction:https://brainly.com/question/13754413
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