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a baseball player hits a baseball into the air with an initial vertical velocity of 65 feet per second. the player hits the ball from a height of 3 feet. write an equation that gives the baseball's height as a function of the time (in seconds) after it is hit. h(t)



Answer :

Y=y0+v0t+1/2at^2
Y=h(t)
Y0=3 feet
V0=65 feet
T=t
A=32.17 feet per second squared

H(t)=3+65t+16.085t^2

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