The equivalent power of coal transported in a mile long train containing 120 cars, each holding 110 tons of coal travelling at 60 mph is 6.04 * 10e12 J
P = E / t
P = Power
E = Energy
t = Time
Distance of train = 1 mile
Number of cars in the train = 120
Tons of coal in 1 car = 110 tons
Velocity of train = 60 mph
Energy of one ton coal = 2.8×10e10 J
Total coal = 120 * 110
Total coal = 13200 tons
Total energy of coal = 13200 * 2.8×10e10
Total energy of coal = 369.6 * 10e12 J
v = d / t
v = Velocity
d = Distance
t = Time
t = d / v
t = 1 / 60
t = 0.017 h
t = 61.2 s
P = ( 369.6 * 10e12 ) / 61.2
P = 6.04 * 10e12 J
P = 6.04 pJ
Therefore, the equivalent power of coal is 6.04 * 10e12 J
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