Answer :
Assume to contrary that the sum of the squares of two odd integers can be the square of an integer. Since, [tex]2[2(m^{2}+n^{2})+2(m+n)+1][/tex] is odd it shows that sum of the squares of two odd integers cannot be the square of an integer.
What is a square?
A quadrilateral with four equal sides is called a square. There are the numerous items in our environment that have a square shape. Equal sides and internal angles that are both 90 degrees distinguish each square shape. Let's find out more about square's characteristics, mathematics, and design.
A square has four corners and is closed, two-dimensional (2D) object.
Assume to contrary that the sum of the squares of two odd integers can be the square of an integer.
Suppose that x,y,z∈Z such that [tex]x^{2} +y^{2} =z^{2}[/tex], and x and y are odd.
Let, x=2m+1 and y=2n+1.
Hence,
[tex]x^{2} +y^{2} =(2m+1)^{2} + (2n+1)^{2}[/tex]
=[tex]4m^{2}+4m+1+4n^{2}+4n+1[/tex]
=[tex]4(m^{2}+n^{2}) + 4(m+n)+2[/tex]
=[tex]2[2(m^{2}+n^{2})+2(m+n)+1][/tex]
Since, [tex]2[2(m^{2}+n^{2})+2(m+n)+1][/tex] is odd it shows that sum of the squares of two odd integers cannot be the square of an integer.
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