let’s say you have a four-digit personal identification number (pin). each digit can be 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9, giving a total of 10 possible numbers for each digit. if a pin is 4 digits, each digit can be any one of the 10 possible numbers, how many different possible combinations are there?

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11-10-2022
Mathematics

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let’s say you have a four-digit personal identification number (pin). each digit can be 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9, giving a total of 10 possible numbers for each digit. if a pin is 4 digits, each digit can be any one of the 10 possible numbers, how many different possible combinations are there?

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abiolataiwo2015 abiolataiwo2015 · Answer 1 · 2022-10-18T09:38:26-04:00

If each digit can be 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9, giving a total of 10 possible numbers for each digit. if a pin is 4 digits, each digit can be any one of the 10 possible numbers, The different possible combinations are there is : 10,000.

Different possible combination

Given :

Digit = 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9

Possible number = 10

Pin = 4 digits

Now let determine the different possible number

Possible number combination = 10 x 10 x 10 x 10

Possible number combination = 10,000

Therefore the combination is 10,000.

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