Answer :

Expected value:

[tex]E(x)=\Sigma(x_i*p(x_i))[/tex]

For the given scenario:

[tex]E(x)=(1*0.25)+(2*0.38)+(3*0.03)+(4*0.16)+(5*0.18)[/tex][tex]E(x)=0.25+0.76+0.09+0.64+0.9[/tex][tex]E(x)=2.64[/tex]

Then, the expected value is 2.64