heysdaddias123
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The question is in the image. Ignore the color underneath each possible answer, that is what I am supposed to do(I am supposed to color in). The question is hard for me.

The question is in the image Ignore the color underneath each possible answer that is what I am supposed to doI am supposed to color in The question is hard for class=


Answer :

mhanifa

Answer:

  • [tex]v_o=v_f-at[/tex]

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Given equation

  • [tex]a=\cfrac{v_f-v_0}{t}[/tex]

Solve it for [tex]v_0[/tex]

Step 1

Multiply both sides by t to get rid of fraction:

  • [tex]at=v_f-v_o[/tex]

Step 2

Find [tex]v_0[/tex] by rearranging the terms:

  • [tex]v_o=v_f-at[/tex]

Correct choice is the last one.

semsee45

Answer:

[tex]v_0=v_f-at[/tex]

Step-by-step explanation:

Given equation:

[tex]a=\dfrac{v_f-v_0}{t}[/tex]

To solve for v₀, rearrange the equation to isolate v₀.

[tex]\textsf{Multiply both sides by $t$}:[/tex]

[tex]\implies at=\dfrac{\left(v_f-v_0\right)t}{t}[/tex]

[tex]\textsf{Cancel the common factor $t$ on the right side}:[/tex]

[tex]\implies at=\dfrac{\left(v_f-v_0\right)\diagup\!\!\!\!t}{\diagup\!\!\!\!t}[/tex]

[tex]\implies at=v_f-v_0[/tex]

[tex]\textsf{Add $v_0$ to both sides}:[/tex]

[tex]\implies at+v_0=v_f-v_0+v_0[/tex]

[tex]\implies at+v_0=v_f[/tex]

[tex]\textsf{Subtract $at$ from both sides}:[/tex]

[tex]\implies at+v_0-at=v_f-at[/tex]

[tex]\implies v_0=v_f-at[/tex]

Solution

[tex]\large\boxed{v_0=v_f-at}[/tex]

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