Answer :
The kinetic energy and speed with which each object hits the ground from highest to lowest is the decreasing order of speed from highest to lowest is 4, 2, 3, and 1.
The masses 1, 2, 3, and 4 have the following kinetic energy : (mgh), = (0.365 kg) (9.8 m/s?) (12.1m) = 43.28 J (mgh), = (0.123 kg) (9.8 m's]) (22.2 m) = 26.75 J (mgh), = (0.612 kg) (9.8 m/s]) (15.3 m) =91.76 J (mgh) A is equal to (0.111 kg) (9.8 m/s?) (27.63 m) = 27.63 J.
So, from highest to lowest, the mass's kinetic energy is distributed as 3, 1, 4, and 2.
To determine an object's velocity, apply the rule of conservation of energy.
= (mgh), (2 (mgh), and (2 (43.28) kg-m/s?)
0.365 kg\s= 15.4 m/s
1 mo? = (meh),\s(2 (mgh).
V = m (26.75 kg- m? /s?)
0.123 kg\s= 20.85 m/s
V3 = 17.31 m/s and v, = 22.31 m/s are also similar.
As a result, the speeds are 4, 2, 3, and 1 in decreasing order from highest to lowest.
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