Answered

A cyclist is traveling at 7m s¹, then accelerates at 2.5m s2 for 15 seconds.
a.
How far did they travel during this time
What was the final speed after 15 seconds?
b.



Answer :

beicker

Answer:

a)

[tex]{ \tt{s = ut + \frac{1}{2} {at}^{2} }} \\ \\ { \tt{s = (7 \times 15) + \frac{1}{2} \times 2.5 \times {15}^{2} }} \\ \\ { \tt{s = 105 + 281.25}} \\ { \tt{s = 386.25 \: m}}[/tex]

b)

[tex]{ \tt{v {}^{2} = {u}^{2} + 2as}} \\{ \tt{ {v}^{2} = {7}^{2} + (2 \times 2.5 \times 386.25)}} \\ { \tt{ {v}^{2} = 1980.25}} \\ { \tt{v = 44.5 \: m}}[/tex]

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