Mass in grams of tin would be required to completely react with 1.50 L of 0.750 M HBr in the following chemical reaction is 36.19g
Mass in gram is the amount of that compound that has the same mass in grams as the formula mass in atomic mass unit
Here given reaction is
Sn + 4HBr → SnBr + 2H₂
Mole of HBr = 1.50L × 0.750 M
= 1.125 mol
From balanced equation 4 mole of HBr react completely with one mole of tin to form the said product
Therefore, 1.125mole of HBr react completely with 1/4×1.125= 0.2812 mole of tin to form the said product
Molar mass of ton is 118.71g/mol
Mass of tin required = 0.2812×118.71
36.19g
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