Answer :
A 25.0-g sample of pure iron at 85 °C is dropped into 75 g of water at 20°C. 22.25 °C is the final temperature of the water-iron mixture.
What is Specific Heat Equation ?
The specific heat equation is represented as
Q = mcΔT
where,
Q = heat energy in Joules
m = mass of substance
c = specific heat
ΔT = change in temperature in K
For iron given that
m = 25 g
c = 0.45 J/g°C
T₁ = 85°C
Now put the values in above formula we get
Q₁ = mcΔT
= 25 × 0.45 × (T₂ - 85)
= 11.25 × (T₂ - 85)
For water given that
m = 75 g
c = 4.184 J/g°C
T₁ = 20°C
Now put the values in above formula we get
Q₂ = mcΔT
= 75 × 4.184 × (T₂ - 20)
= 313.8 × (T₂ - 20)
Now,
Heat is generated by iron = Heat is gained by water.
Q₁ = -Q₂
11.25 × (T₂ - 85) = - 313.8 × (T₂ - 20)
325.05 T₂ = 7232.25
T₂ = 22.25 °C
22.25 °C is the final temperature of the water-iron mixture.
Learn more about the Specific heat here: https://brainly.com/question/21406849
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