A tennis ball is dropped from 1.58 m above the
ground. It rebounds to a height of 0.979 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s-
Answer in units of m/s.

When gravity first exerts force on an object, its initial velocity defines how quickly the object moves. The final velocity, on the other hand, is a vector number that gauges a moving body's speed and direction after it has reached its maximum acceleration. By applying the third equation of motion during the downward motion, we can quickly determine the final velocity or the velocity at which the ball reaches the ground. Following is the third equation of motion:

Where g = the acceleration of gravity = 9.8 m/s², h = the height = 1.16 m, and Vf = the final velocity of the ball =?

Vi = Ball's Initial Velocity = 0 m/s (Since the ball was at rest initially)

As a result, when we use these values in the equation, we obtain:

(2) Vf2 = (9.8 m/s²) (1.16 m) - (0 m/s)

Vf = 4.77 m/s

Learn more about velocity here-

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A tennis ball is dropped from 1.58 m above the ground. It rebounds to a height of 0.979 m. With what velocity does it hit the ground? The acceleration of gravity is 9.8 m/s- Answer in units of m/s.

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Other Questions

A tennis ball is dropped from 1.58 m above the
ground. It rebounds to a height of 0.979 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s-
Answer in units of m/s.