2 moles of AlCl3 were reacted as shown by the balanced reaction below.

How many moles of MgCl2 formed?

2 AlCl3 + Mg3P2 → 2 AlP + 3 MgCl2



Answer :

If 2 moles of AlCl₃ reacts as shown in the balanced equation, 3 moles of MgCl₂ will be produced.

How to calculate number of moles?

Stoichiometry is the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, aluminum chloride reacts with magnesium phosphate to produce aluminum phosphate and magnesium chloride as follows:

2AlCl3 + Mg₃P₂ → 2AlP + 3MgCl₂

Based on the above balanced reaction, 2 moles of aluminum chloride (AlCl₃) formed 3 moles of magnesium chloride (MgCl₂).

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