Answer :

Answer:   -1

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Work Shown:

Recall that the imaginary number i has the definition of [tex]i = \sqrt{-1}[/tex]

List out the first few powers of i

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = -i
  • i^4 = 1

I'm skipping steps when I listed out those terms, so let me know if you need to see them.

The process repeats every 4 items. This means we'll divide the exponent by 4 to look at the remainder.

Let's do that for the first exponent

12/4 = 3 remainder 0

The remainder 0 tells us that i^12 = i^0 = 1

Also,

22/4 = 5 remainder 2

The remainder 2 means i^22 = i^2 = -1

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In short:  i^12  = 1 and i^22 = -1

which means 6i^12 + 7i^22 = 6(1) + 7(-1) = -1