Answer :

Eduard22sly

1. The limiting reactant is CuCl₂

2. The theoretical yield of copper is 0.24 g

Balanced equation

2Al + 3CuCl₂ —> 2AlCl₃ + 3Cu

The following were obtained from the balanced equation:

  • Molar mass of Al = 27 g/mol
  • Mass of Al from the balanced equation = 2 × 27 = 54 g
  • Molar mass of CuCl₂ = 63.55 + (2 × 35.5) = 134.55 g/mol
  • Mass of CuCl₂ from the balanced equation = 3 × 134.55 = 403.65 g
  • Molar mass of Cu = 63.55 g/mol
  • Mass of Cu from the balanced equation = 3 × 63.55 = 190.65 g

From the balanced equation above,

54 g of Al reacted with 403.65 g of CuCl₂ to produce 190.65 g of Cu

1. How to determine the limiting reactant

From the balanced equation above,

54 g of Al reacted with 403.65 g of CuCl₂

Therefore,

0.5 g of Al will react with = (0.5 × 403.65) / 54 = 3.74 g of CuCl₂

From the above calculation, we can see that a higher amount (i.e 3.74 g) of CuCl₂ than what was given (i.e 0.5 g) is needed to react completely with 0.5 g of Al.

Thus, CuCl₂ is the limiting reactant.

2. How to determine the theoretical yield of copper

From the balanced equation above,

403.65 g of CuCl₂ reacted to produce 190.65 g of Cu

Therefore,

0.5 g of CuCl₂ will react to produce = (0.5 × 190.65) / 403.65 = 0.24 g of Cu

Thus, the theoretical yield of Cu is 0.24 g

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