The electric field at 100cm is 5.39 x 10² N/C.
We need to know about the electric field to solve this problem. The electric field is the area affected by electric force. The magnitude of electric field at a distance from long infinite length and constant charge per unit length is given by
E = λ / (2πε₀d)
From the question above, we know that
λ = 30 nC/m
λ = 30 x 10¯⁹ C/m
d = 100 cm = 1 m
By substituting the given parameter, we get
E = λ / (2πε₀d)
E = 30 x 10¯⁹ / (2π . 8.85 x 10¯¹² . 1)
E = 5.39 x 10² N/C
Hence, the electric field at 100cm is 5.39 x 10² N/C.
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