Answer :
If 160.0 g of radioactive iron (59Fe ) is received in the lab today, Then the percentage of the original left after 180 days is 6.25 %.
Radioactive elements are those elements which are made up of those atoms whose nuclei is unstable and emits radiations or undergoes radioactive decay to attain stability or to form stable nuclei.
Given -
t = 180 days
t1/2 = 45 days
So,
n = t = 180 = 4
t1/2 45
Amount of the remaining radioactive iron,
R = R°
2n
where, n = 4
R = 1 = 0.0625
R° 2₄
To calculate percentage of original sample -
percentage of original sample of iron = R x 100
R°
= 0.0625 x 100
= 6.25 %
After 180 days, or 4 half lives, the percentage of radioactive iron remaining is 6.25%.
To learn more about radioactive element,
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