A 2.64 L aqueous solution of KOH. The solution has a density of 1.29 g/mL.
Calculate the molarity, Molality, and mass percent concentration of the solution.



Answer :

The molarity of the solution is 0.023 M and the molality of the solution is  17.9 m.

What is the molality?

The concentration of a solution is defined as the amount of substance in a solution. Now we are told that we have a solution of  2.64 L aqueous solution of KOH. The solution has a density of 1.29 g/mL.

Density of the solution = 1.29 g/mL

Volume of the solution =  2.64 L

mass of the solution = 1.29 g/mL * 2.64 L = 3.4 g

Number of moles of the solute =  3.4 g/56 g/mol = 0.061 moles

Molarity =  0.061 moles/2.64 L = 0.023 M

Molality of the solution = 0.061 moles/3.4 * 10^-3 Kg = 17.9 m

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