The molarity of the solution is 0.023 M and the molality of the solution is 17.9 m.
The concentration of a solution is defined as the amount of substance in a solution. Now we are told that we have a solution of 2.64 L aqueous solution of KOH. The solution has a density of 1.29 g/mL.
Density of the solution = 1.29 g/mL
Volume of the solution = 2.64 L
mass of the solution = 1.29 g/mL * 2.64 L = 3.4 g
Number of moles of the solute = 3.4 g/56 g/mol = 0.061 moles
Molarity = 0.061 moles/2.64 L = 0.023 M
Molality of the solution = 0.061 moles/3.4 * 10^-3 Kg = 17.9 m
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