ΔHdissolution = 27×10⁻⁵
A calorimeter is a device used for heat measurements necessary for calorimetry
Here given data is 4.79g = KBr and are dissolved in 109.00g water and temperature is 21.08°C and according to calorimeter heat of capacity = 1.84 J/°C
We have to calculate enthalpy of dissolution of KBr = ? ΔHdissolution = 27×10⁻⁵
KBr+H₂0→KBr ΔH=?
qreaction = -qcal
1.79×1.84(-2.4) = 0.8936 J
1000 = -0.0008936
4.79+109.00 = 522.11 g
qcal = 522.11 g×1.84(-2.4) = -2305 J
qreaction = -qcal = -2305 J
n(KBr) = 4.79/74.55gmol⁻¹ = 0.0642mol
2305/ 0.0642mol = 0.00002787mol⁻¹
= 27×10⁻⁵
ΔHdissolution = 27×10⁻⁵
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