Answer :
The specific heat capacity of the metal is
1.06j/g.°C .
Given,
weight of a metal sample = m = 25 g
initial temperature = 100°C
final temperature = 25°C
change in temperature = ∆T = (100-25) °C = 75°C
The heat energy released by the metal
= q = 2kj = 2000j
According to the formula of specific heat capacity,
q = c × m × ∆T
where, c is the specific heat capacity.
c = q / (m× ∆T)
c = 2000j / ( 25g × 75°C)
c = 2000j / 1875 g.°C
c = 1.06 j/g.°C
Hence, the specific heat capacity of the metal is
1.06j/g.°C .
Specific heat capacity :
It is the amount of heat required to raise the temperature of the system of one unit mass by one degree.
specific heat capacity can be calculated by the formula given by,
q = c×m×∆T
c = q/m×∆T
where, q = is the amount of heat required to raise the temperature by 1° .
c = specific heat capacity
m = mass
∆T = change in temperature
If the magnitude of heat capacity is large, then there is a small rise in temperature by s given amount of heat.
heat capacity of water is large.
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