Answer :
The heat capacity of the liquid is 1.53J/ g°C
Formula:
Q = m × c × ΔT
Q = m × c × ( T₂ - T₁ )
where,
Q = amount of heat gained or lost ⇒ 53J
m = mass of liquid ⇒ 15g
c = specific heat of liquid ⇒ ?
ΔT = change in temperature
T₁ = initial temperature ⇒ 10.7°C
T₂ = final temperature ⇒ 13°C
Heat capacity measures the energy required to raise the temperature of a unit mass of a substance by a unit degree
53J = 15g × c × ( 13 - 10.7 )°C
c = 53/ (15 × ( 13 - 10.7 )°C)
= 53/( 15 × 2.3)
= 1.53 J/ g°C
Thus we can conclude that the heat capacity of the liquid is 1.53J/ g°C
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