If the mass of a planet is 3. 10 1024 kg, and its radius is 2. 00 106 m, what is the magnitude of the gravitational field, g, on the planet's surface?

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16-09-2022
Physics

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If the mass of a planet is 3. 10 1024 kg, and its radius is 2. 00 106 m, what is the magnitude of the gravitational field, g, on the planet's surface?

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aditmarkas98 aditmarkas98 · Answer 1 · 2022-09-20T23:51:28-04:00

The gravitational field strength is 51.6925 N/kg.

We need to know about the gravitational field to solve this problem. The gravitational field is the area where affected by gravitational force. The magnitude of the gravitational field can be calculated by this equation

g = G . m / r²

where g is the gravitational field, G is gravitational constant (6.67 x 10¯¹¹ Nm²/kg²), m is the mass of the planet and r is the radius of the planet

From the question above, we know that

m = 3.10 x 10²⁴ kg

r = 2.00 x 10⁶ m

By substituting the given parameter, we get

g = G . m / r²

g = 6.67 x 10¯¹¹ . 3.10 x 10²⁴/ (2.00 x 10⁶)²

g = 51.6925 N/kg

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