The ball that is projected 125 meters straight upward has a total time in the air of: 10.1 s
The formulas for the vertical launch upward and the procedures we will use are:
- y max = v₀²/(2*g)
- t max = v₀/ g
- t(of)=2*t max
Where:
- v₀ = initial velocity
- g = gravity
- y max = maximum height
- t max = time to reach maximum height
- t(of) = time of flight
Information about the problem:
- g = 9.8 m/s²
- y max= 125 m
- v₀ = ?
- t max =?
- t(of) =?
Applying the maximum height formula and clearing the initial velocity we get:
y max = v₀²/(2*g)
v₀ = √(y max * (2*g))
v₀ = √( 125 m * (2 * 9.8 m/s²))
v₀ = √( 125 m * 19.6 m/s²)
v₀ = √2450 m²/s²
v₀ = 49.497 m/s
Applying the maximum time formula we get:
t max= v₀ / g
t max= 49.497 m/s / 9.8 m/s²
t max = 5.050 s
Applying the time of flight formula, we get:
t(of) =2 * t max
t(of) =2 * 5.050 s
t(of) = 10.1 s
What is vertical launch upwards?
In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.
Learn more about vertical launch at: brainly.com/question/13962796
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