draw the structure of the two tertiary (3°) alcohols with the molecular formula c7h16o that contain a only one ch3 group attached to the main carbon chain.



Answer :

The structure that will be formed is: 2-methyl, hexan-2-ol

According to the query, the main chain has one distinct methyl group coming off of it. As a result, if we take away one carbon from the formula, we are left with six carbons, indicating that our structure has a six-carbon main chain.

CH₃ CH₂ CH₂ CH₂ CH₃

Additionally, it is said that we possess two tertiary alcohols. However, as the formula is C₇H₁₆O, only one more alcohol group can be added. When the functional group -OH is joined to a tertiary carbon, which is a carbon with only one bond, the result is a tertiary alcohol. Since adding methyl groups and alcohol to the same carbon is the only way to convert our 6-carbon chain into a tertiary alcohol, we are unable to add the -OH to either end of the chain. Therefore, in our 6-carbon chain, the 2-, 3-, 4-, or 5-carbon must receive the -OH:

CH₃-CH-CH₂-CH₂-CH₂-CH₃

          |

         OH

Our structure now comprises 6 carbons, a 6-carbon chain, and a tertiary alcohol. We will extend our 6-carbon chain by one methyl group. We require a distinct methyl group that extends from the initial 6-carbon chain. We are limited to placing this methyl group on the 2-carbon. As a result, the structure we seek is:

    CH₃

         |

CH₃-C—CH₂- CH₂- CH₂-CH₃

         |

       OH

To learn more about the structure of tertiary alcohol visit the link:

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