Answer :
The expressions for the magnitude of the electrical field strength inside the cylinder, r is,
E = λ/2ε₀πr
What is electric field?
The electric field is the field, which is surrounded by the electrical charged. the electrical field is the electric force per unit charge. Here an extended , thin straight wire with linear charge density λ runs down the middle of a thin, hollow metal cylinder of radius R.
As the electric flux is the product of electric flux and the area of the cylinder. Thus,
φ = E(2πrL) .................1
This electric flux also can be given as,
φ = λL/ε₀ ......................2
Where, ( λ) is that the linear charge density. On comparing both the equation, we get,
Ε(2πrL) = λL/ε₀
E = λ/ 2ε₀πr
The cylinder features a net linear charge density 2λ where λ is positive. Thus for this hollow cylinder, the electrical filed can be given as,
E = λ/2ε₀πr
For charge inside the cylinder, where r < R, are often expressed with the following expression,
E = λ/2ε₀πr
Charge density :
The charge density is that the measure of electric charge per unit area of a surface, or per unit volume of a body or field. The charge density tells us what proportion charge is stored in a particular field. Charge density are often determined in terms of volume, area, or length.
Learn more about Electric field :
brainly.com/question/14372859
#SPJ4
