The empirical formula of the compound is [tex]Fe_{1} I_{2}[/tex].
Given,
Mass of Fe= 17.90 g
Mass of metal iodide = 99.24 g
Now we have to calculate the mass of iodide.
Mass of I = Mass of metal iodide - Mass of Fe
Mass of I = 99.24 - 17.90
Mass of I = 81.34 g
To formulate the empirical formula, we need to follow some steps:
First, we convert the given masses into moles.
Moles of Fe = Given mass/ molar mass = 17.90/55.93 = 0.32 moles
Moles of I = given mass/ molar mass = 81.34/126 = 0.64 moles
To calculate the mole ratio, we divide each value by the smallest number of moles that is 0.32 moles.
For Fe = 0.32/0.32 = 1
For I = 0.64/0.32 = 2
Hence the mole ratio is
Fe:I = 1:2
Thus, the empirical formula would be [tex]Fe_{1} I_{2}[/tex]
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