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steam is accelerated in a steady-flow nozzle from a low velocity to a velocity of 210 m/s at a rate of 3.2 kg/s. if the temperature and pressure of the steam at the nozzle exit are 200 ºc and 600 kpa, what is the exit area of the nozzle?



Answer :

The exit area of the nozzle is 0.000861 m².

Velocity = 280 m/s

Rate = 2.5 kg/s

Pressure = 2 MPa

Temperature = 400°C

Using equation of ideal gas

PV= RT

V= RT/P

V= 0.0965 [tex]m^{3}[/tex]/ kg

Using equation of continuity

(dm/dt) = [tex]A_{1}[/tex]v/V

[tex]A_{1}[/tex]= 0.000861 [tex]m^{2}[/tex].

What is an ideal gas?

A theoretical gas known as an ideal gas is made up of several randomly moving point particles with no interparticle interactions. Because it abides by the ideal gas law, a condensed equation of state, and is amenable to statistical mechanics analysis, the ideal gas concept is helpful.

To learn more about ideal gas from the given link:

brainly.com/question/28257995

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