Answer :
The speed of the ball when it left his foot is 11.13 m/s.
The given parameters;
distance of the goal, d = 17 m
angle of projection of the ball, = 38°
height of the cross bar, H = 2.4 m
The speed of the projectile will be calculated by applying the formula for maximum height reached by a projectile;
u=2x9.8x2.4/sin2(38)
u=11.13
Thus, the speed of the ball when it left his foot is 11.13 m/s.
What is projectile?
An object that is driven by the application of an external force and then moves freely while being affected by gravity and air resistance is referred to as a projectile. Despite the fact that all items traveling through space are projectiles, they are frequently used in sports and warfare.
Therefore,
u=2x9.8x2.4/sin2(38)
u=11.13
To learn more about projectile from the given link:
https://brainly.com/question/11422992
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