choose the correct realistic problem for which this is the correct equation. choose the correct realistic problem for which this is the correct equation. at what distance along the axis of a charged disk is the electric field strength double its value at the center of the disk? give your answer in terms of the disk's radius r . at what distance along the axis of a charged disk is the electric field strength half its value at the center of the disk? give your answer in terms of the disk's radius r . at what distance along the axis of a charged square is the electric field strength double its value at the center of the square? give your answer in terms of the square's side r . at what distance along the axis of a charged square is the electric field strength half its value at the center of the square? give your answer in terms of the square's side r .

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13-09-2022
Physics

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choose the correct realistic problem for which this is the correct equation. choose the correct realistic problem for which this is the correct equation. at what distance along the axis of a charged disk is the electric field strength double its value at the center of the disk? give your answer in terms of the disk's radius r . at what distance along the axis of a charged disk is the electric field strength half its value at the center of the disk? give your answer in terms of the disk's radius r . at what distance along the axis of a charged square is the electric field strength double its value at the center of the square? give your answer in terms of the square's side r . at what distance along the axis of a charged square is the electric field strength half its value at the center of the square? give your answer in terms of the square's side r .

Answer :

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AnnuG AnnuG · Answer 1 · 2022-09-18T08:11:16-04:00

The correct realistic problem for the given equation is problem 1.

We know that,

Electric field of a charged disc at a distance along its axis is given by,

E = σ / 2 ε ( 1 - x / √ ( [tex]x^{2}[/tex] + [tex]r^{2}[/tex] ) )

Electric field at the centre of a charged disc is given by,

[tex]E_{c}[/tex] = σ / 2 ε ( Since at centre, x = 0 )

Distance along the axis of a charged disk, where electric field strength's value is half its value at the center of the disk.

[tex]E_{x}[/tex] = [tex]E_{c}[/tex] / 2

σ / 2 ε ( 1 - x / √ ( [tex]x^{2}[/tex] + [tex]r^{2}[/tex] ) ) = ( σ / 2 ε ) / 2

x / √ ( [tex]x^{2}[/tex] + [tex]r^{2}[/tex] ) = 1 / 2

4 [tex]x^{2}[/tex] = [tex]x^{2}[/tex] + [tex]r^{2}[/tex]

3 [tex]x^{2}[/tex] = [tex]r^{2}[/tex]

x = r / √ 3 ,which is the correct distance, when magnitude is half its value from centre.

Electric field is a field that surrounds electrically charged particles that exerts force on other charged particles in the field.

Therefore, the given equation is suitable for Electric field of a charged disc at a distance along its axis where electric field strength's value is half its value at the center of the disk.

The given question is incomplete. The completed question is

You are given the following equation to solve a problem:

σ / 2 ε ( 1 - x / √ ( [tex]x^{2}[/tex] + [tex]r^{2}[/tex] ) ) = [tex]E_{c}[/tex] = σ / 2 ε

Choose the most realistic problem for which this could be the correct equation.

1 ) At what distance along the axis of a charged disk is the electric field strength half its value at the center of the disk? Give your answer in terms of the disk's radius R.

2 ) At what distance along the axis of a charged disk is the electric field strength double its value at the center of the disk? Give your answer in terms of the disk's radius R.

3 ) At what distance along the axis of a charged square is the electric field strength double its value at the center of the square? Give your answer in terms of the square's side R.

4 ) At what distance along the axis of a charged square is the electric field strength half its value at the center of the square? Give your answer in terms of the square's side R.

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