The force between two masses m and m is 8.0 n when they are a certain distance r apart. what will the force between these two masses be if the distance between them is increased by a factor of four?



Answer :

The force between two masses when the distance between those two masses is increased by a factor of four is 0.5 N

We know that,

F = G [tex]m_{1}[/tex] [tex]m_{2}[/tex] / [tex]r^{2}[/tex]

where,

F = Force

G = Constant

[tex]m_{1}[/tex], [tex]m_{2}[/tex] = Masses

r = Distance between those two forces

Given that,

F = 8 N

When the distance between those two masses is increased by a factor of four,

[tex]F^{'}[/tex] = G [tex]m_{1}[/tex] [tex]m_{2}[/tex] / [tex]( 4r)^{2}[/tex]

[tex]F^{'}[/tex] = F / 16

[tex]F^{'}[/tex] = 8 / 16 = 1 / 2

[tex]F^{'}[/tex] = 0.5 N

Force is a phenomenon which can cause an objects motion to change. It causes an object with mass to change its velocity.

Therefore, the force between two masses when the distance between those two masses is increased by a factor of four is 0.5 N

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