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the freezing point of a cyclohexane sample is 6.20 °c. a solution is prepared by dissolving 0.4660 g of an unknown solute in 36.0 g cyclohexane. the freezing point of the resulting solution is 4.11 °c.



Answer :

The answer for the given problem would be 123.87 g

Molar mass of an unknown solid = ?

Delta Temperature = kf * molality for finding molality

Molality = moles / kg solvent

Moles = grams / molar mass

Mass of solute mixed in cyclohexane = 0.4 * 609

Solute mixed in cyclohexane and mixed in cycloheptene= 0.4^2 * 1000 / 36 π

Del Temperaturef = kf * molality

= 2.0920 * 0.4 * 1004 / 36 * 2.09

M = 9320 / 73.29

= 123.87

Molar mass of unknown solvent = 123.87 g

Hence the answer is 123.87 g

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