The deceleration of the car from a velocity of 100ms-1 to a final velocity of 20ms-1 in 10 seconds is 8ms-2.
We are aware that acceleration refers to an object's rate of increase in speed, and deceleration refers to an object's rate of decrease in speed.
Because it must be reported as a magnitude and a direction, acceleration is a vector. Negative and positive signs are used to denote the direction in circumstances of one-dimensional motion. Negative indicators indicate that the object is slowing down.
The unit of measurement is the meter per second square, or ms-2.
We know that
v= u + at,
where,
v= final velocity
u= initial velocity
t= time
a= acceleration
According to the question,
u= 100ms-1
v= 20ms-1
t= 10s
a=?
so, v = u + at
substituting the values in the equation, we get:
20 = 100 + 10a
a= -8 ms-2
Here, the negative sign shows that the car is decelerating,
Thus, deceleration is 8ms-2.
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