A body of mass 6kg falls under action of gravity at initial position a its pe is 480 j and ke is 0j during its downwards journey at point b its energies will be



Answer :

Answer:

Explanation:

Kinetic energy will be mg×( total height - x ) and potential energy will be 6 g x .

Let assume point B is located at height x unit from the surface,

As we know , potential energy = m g h ( where m = mass of the body , g = gravitational acceleration and h = height from the surface )

so potential energy at point A = 480 j  or 6gh ( h = total height from surface )and for the point B it is , 6gx ( where g = 9.8 m/s²) .

At point A , total kinetic energy is 0 or, 1/2 mu² = 0

∵ u = 0,

So, initial velocity is zero ,

Now we will apply  Newton's formula ,

and we will get , v² = u² + 2as

or, v² = 0 + 2 g h ( as acceleration = gravitational acceleration = g ; s = height h )

[ multiplying both side with 1/2 m ]

or , 1/2 m v² =  m g h

Kinetic energy = 1/2 m v² = m g h

[ h = ( total height - x )  at point B .  ]

Kinetic energy = m g ( total height - x )

To know more about potential energy ,

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