The km of an enzyme is 5. 0 mm. Calculate the substrate concentration when this enzyme operates at one‑quarter of its maximum rate.



Answer :

The concentration of the substrate is found to be 1.66mm.

Given that the Km of enzyme is 5mm.

Vo =Vmax/4

We know that the formula for Vo

Vo = Vmax[S] /[S] +km

Vmax/4 = Vmax[S] /[S] +km

1/[S] = [S]/ [S] + Km

[S] + Km = 4[S]

Km = 3[S]

[S] = km/3

=5/3mm

[S]= 1.67mm

Thus, the concentration of the substrate is found to be 1.66mm.

The substrate concentration at which half of the enzyme active sites are saturated with the substrate is known as the Km value.  The relationship between the value of KM and the enzyme’s affinity for its substrate is inversely proportional.

It provides information regarding the substrate affinities of enzymes. Km is the substrate concentration at which half of Vmax is reached. One can determine if a given enzyme-substrate system needs more enzymes or substrate to speed up the enzymatic reaction by knowing the Km value of the system.

To learn more about km value of substrate, refer this link.

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