The velocity of the car was 4.93m/s and the direction was northeast.
It is given,
time of the trip = t = 3 minutes = 180 seconds
1st distance A = 1500ft = 457.2m east
2nd distance B = 2500ft = 762m north
We are asked to find the average velocity.
First, we get the resultant distance magnitude by applying Pythagoras theorem to find the hypotenuse.
[tex]A^{2} + B^{2} =C^{2} \\C=\sqrt[]{A^{2} +B^{2} } \\C=\sqrt{457.2^{2} +762^{2} } \\C= 888.63m[/tex]
Then we have
Velocity = Distance/time
Velocity = 888.63/180
Velocity = 4.93 m/s
Then the direction is northeast.
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