How many turns of the double helix must be unwound during replication of the e. coli chromosome?

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12-09-2022
Biology

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How many turns of the double helix must be unwound during replication of the e. coli chromosome?

Answer :

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tutorconsortium31 tutorconsortium31 · Answer 1 · 2022-09-14T11:10:07-04:00

It is given in the question that the E. coli chromosome contains 4,639,221 base pairs.

As we know that the one turn of double-stranded chromosome contains ten base pairs.

Therefore, if we need to find the number of turns for 4,639,221 base pairs, then we need to divide it by ten.

Hence, the number of turns of the double helix that is required for unwinding during replication of E. coli is 463922.

What is E. coli ?

E. coli or Escherichia coli is a type of bacteria that is known to reside in our intestines. E. coli belongs to the family of Enterobacteriaceae. When this bacteria is found in urine, then it can cause some dangerous urine infections, ultimately infecting urinary tract infections.

Learn more about E. coli here:

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