A solution is prepared by dissolving 50.4 g sucrose (c12h22o11) in 0.332 kg of water. the final volume of the solution is 355 ml. for this solution, calculate the molarity.

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12-09-2022
Chemistry

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A solution is prepared by dissolving 50.4 g sucrose (c12h22o11) in 0.332 kg of water. the final volume of the solution is 355 ml. for this solution, calculate the molarity.

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tripatsingh039 tripatsingh039 · Answer 1 · 2022-09-14T16:30:13-04:00

The molarity of the sucrose solution is found to be 0.4146M

The term "molarity" (also known as "molar concentration," "amount concentration," or "substance concentration") refers to the amount of a substance per unit volume of the solution and is used to describe the concentration of a chemical substance, specifically a solute, in a solution.

Given:

Mass of sucrose, m = 50.4g

Volume of solution, v = 355ml = 0.355L

Molecular weight of sucrose = 342.3g/mol

To find:

Molarity, M = ?

Formula:

Molarity = amount of solute, n (moles) / volume of solution, v (L)

Calculations:

No. of moles of sucrose, n = mass of sucrose x (1 mole / molecular weight of sucrose)

n = 50.4 x (1/342.3)

n = 0.1472 moles

M = 0.1472 / 0.355

Molarity = 0.4146M

Result:

The sucrose solution has a molarity of 0.4146M.

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