Toss a ball of mass 3 kg up initially with velocity 9.5 m/s. how high does it go in meters? simply enter number here without units or other symbols.



Answer :

The ball reaches a maximum height of 15.1m.

The beginning velocity, the launch angle, and the acceleration due to gravity all affect an object's maximum height when it is moving as a projectile. Its measurement is in "meters." The formula for maximum height is:

Maximum height = (initial velocity)^2(Sine of launch angle)^2/ 2×acceleration due to gravity

The path taken by projected objects from a plane that land on the same horizontal surface is always vertically symmetrical.

The time of flight is the amount of time between when an object is projected and when it lands. This duration is influenced by the projectile's starting speed and projection angle. The projectile will have reached its maximum height when it has a vertical velocity of zero magnitudes. Additionally, gravity will take over and continue to accelerate the thing downward.

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