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in a slap shot, a hockey player accelerates the puck from a velocity of 11 m/s to 50 m/s in the same direction. if this takes 3.33x10^-2 s, calculate the distance over which the puck accelerates



Answer :

asuwafohjames

The distance traveled by the puck is 0.203 m.

What is distance?

This can be defined as the length between two points.

To calculate the distance which the puck accelerate, we use the formula below.

Formula:

  • S = (v+u)t/2.......... Equation 1

Where:

  • S = Distance
  • v = Final velocity
  • u = Initial velocity
  • t = Time

From the question,

Given:

  • v = 50 m/s
  • u = 11 m/s
  • t = 3.33×10⁻³ s

Substitute these values into equation 1

  • S = (50+11)3.33×10⁻³ /2
  • S = 0.203 m

Hence, the distance traveled by the puck is 0.203 m.

Learn more about distance here: https://brainly.com/question/2854969

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