Answer :
The frequency of 0.5 kg mass oscillating on a spring with spring constant k = 5 n/m will be 0.50 Hz.
The oscillation of a spring is governed by the following formulas :
ω = √k/√m
T = 2π/ω = 2π (√m√/k)
f = 1/T = 1/2π(√k/√m)
Here ω represents the angular frequency
T is the time period
And f is the frequency
We can use the third formula to calculate the frequency by putting the given values in it.
f = 1/2π √k/√m
f = 1/2π √5/√0.5
f = 1/2π x √10
f = 1/2 x 3.16/3.14
f = 0.50 Hz
Hence, the frequency of 0.5 kg mass oscillating on a spring with spring constant k = 5 n/m will be 0.50 Hz.
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