Answer :
The correct answer of this question is 4 pairs of gene are involved.
First we have to calculate total number of individuals that are formed in f2 generation i.e.. 1+8+28+56+70+56+28+8+1= 256
From above statement we can find out that out of 256 individuals 2 are showing the extreme/dominant characters that is the parental characters and all other individuals show recombination characters or characters different from the parental one.
If the proportion of F2 individuals displaying either of the two most extreme parental phenotypes can be calculated using the following formula, the number of genes in cases of polygenic inheritance can be estimated by the formula,
either of two extreme cases= 1/4ⁿ
=1/ 256 = 1/4ⁿ
On solving this we get n= 4
Thus 4 pairs of genes are involved in the f2 generation of an experimental cross.
A Polygenic inheritance is a phenomenon in which polygene is a gene that works in concert with other genes to slightly influence phenotypes.
Multiple alleles, such as the ABO blood group system, which is regulated by three alleles, are different from polygenic inheritance in that multiple alleles occurs when three or more alleles are present in the same locus and any two of those alleles are present in an organism.
To learn more about polygenic inheritance, refer this link.
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