Answer :

49x⁶y¹⁰ tiles are required to cover the floor;

Side length of the square floor = 7x⁵y⁶;

Side length of the square tile = x²y;

Area of the given floor is = (7x⁵y⁶)²  sq units

                                          = 7²x¹⁰y¹² sq units

                                          = 49x¹⁰y¹² sq units.

Area of a tile is = (x²y)² sq units

                         = x⁴y² sq units.

Let no. of tiles required be 'n';

Area of square floor = (No. of square tiles) × (Area of 1 square tile);

49x¹⁰y¹² = n × x⁴y²;

 n = 49x⁶y¹⁰;

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