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Two cyclists, 54 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as
the other. If they meet 3 hours later, what is the speed (in mi/h) of the faster cyclist?
a. Write an equation using the information as it is given above that can be solved to answer this problem.
Use the variable r to represent the speed of the slower cyclist.
b. What is the speed of the faster cyclist?
mi/hr



Answer :

facundo3141592

The equation that we need to solve is:

(S + 2*S)*3h = 54mi

The speed of the slower cyclist is 6 mi/h

The speed of the faster cyclist is 12 mi/h.

How to write an equation that models this situation?

Let's define S as the speed of the slower cyclist, thus 2*S will be the speed of the other cyclist.

They travel in opposite directions, and after 3 hours the travel a combined distance of 54 miles, then we can write the equation:

(S + 2*S)*3h = 54mi

With that equation, we can determine the speeds of the cyclists.

Solving for S we get:

(S + 2*S)*3h = 54mi

3*S = 54mi/3h = 18 mi/h

S = (18 mi/h)/3 = 6 mi/h

Then the speed of the slower cyclist is 6 miles per hour, and the speed of the faster cyclist is twice that, so it is 2*6 mi/h = 12 miles per hour.

If you want to learn more about speed:

https://brainly.com/question/4931057

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