After d days the total number of lily in the ponds are . It is an simple example of geometric progression.
The formula to calculate the sum of the first n terms of a geometric progression is given by: Sn = a[(rn – 1)/(r – 1)]. Where r is the common ratio and a is the first number of the progress.
Lilly pond starts with 1 Lilly pad, so a = 1and every day amount doubles, so r = 2. Total number of day is d, so n = d.
Therefore, the total number of lilly in the pond is = 1x[(2d-1)/(2-1)] = 2d-1.
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