Answer :

EtherRial

Explanation:

Q = charge in C(coulombs)

I = current in A(amps)

t = time in s(seconds)

Q = I × t

I = Q / t

Substitute in given values.

I = 300C / 30s

= 10A

Hope this helped! ^^

id1001265

The electric current generated by a charge of 300 coulombs passing through the cross section of a conductor in a time of 30 seconds is: 10 A

To solve this exercise the formula for electric current and the procedure we will use is:

I= q/t

Where:

  • I = intensity of the electric current
  • q= electric charge
  • t = time

Information about the problem:

  • q= 300 C
  • t = 30 s
  • I=?
  • 1 C/s = 1 A

Applying the electric current intensity formula we have:

I= q/t

I= 300 C / 30 s

I= 10 A

What is electric current intensity?

In physics the intensity of the electric current is the magnitude that expresses the amount of electric charge or electric current in coulomb (c) that passes through an electrical conductor in a given time in seconds (s). Its unit of measurement in the international system is the Ampere (A).

Learn more about electric current at: brainly.com/question/1100341

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