Answer :
The electric field at a point halfway is 18.37 x 10⁵ N/C.
We need to know about the electric fields to solve this problem. The electric field produced by a single-point positive charge is a radial field, whose strength is given by the equation
E = k.Q/r²
where E is the electric field, Q is the charge and r is the radius.
From the question above, we know that
k = 9 x 10⁹ Nm²/C²
Q1 = -5μC = -5 x 10¯⁶ C
Q2 = 4μC = 4 x 10¯⁶ C
x = 21 cm = 0.21 m
from midpoint (r = 0.105 m)
The electric field directly outward from Q2 to Q1 so that the total electric field between the charges will be added up.
Etotal = E1 + E2
Etotal = k.Q1/r² + k.Q2/r²
Etotal = k/r² x (Q1 + Q2)
Etotal = 9 x 10⁹/(0.21)² x (5 x 10¯⁶ + 4 x 10¯⁶)
Etotal = 18.37 x 10⁵ N/C
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