a string along which waves can travel is 2.70 m long and has a mass of 260.0 g. the tension in the string is 36.0 n. what must be the frequency of traveling waves of amplitude 7.70 mm for the average power to be 58.0 w?



Answer :

By power transmitted by string, the frequency must be 163.31 Hz.

We need to know about power transmitted to solve this problem. The power transmitted by a  wave on string can be determined by this equation

P = 1/2 . μ . ω² . A² . v

where P is the power, μ is mass per unit length of string, ω is angular speed, A is amplitude and v is wave propagation speed.

the wave propagation can be determined as

v = √(F.l/m)

where F is the string tension, l is length and m is the mass.

From the question above, we know that:

l = 2.7 m

m = 260 g = 0.26 kg

F = 36 N

A = 7.7 mm = 0.0077 m

P = 58 W

Find the mass per unit length

μ = m / l

μ = 0.26 / 2.7

μ = 0.096 kg / m

Find the wave propagation speed

v = √(F.l/m)

v = √(36. 2.7 /0.26)

v = √(373.85)

v = 19.34 m/s

Find the angular speed

P = 1/2 . μ . ω² . A² . v

58 = 1/2 . 0.096 . ω² . 0.0077² . 19.34

ω² = 1053777.29

ω = √1053777.29

ω = 1026.54 rad/s

Find the frequency

ω = 2πf

1026.54 = 2 . 3.14 . f

f = 163.31 Hz

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