Answered

2. Which is the equation of a line that passes through (5, -2) and is
perpendicular to y = 7x-8?
h 3
e. y - 5 = 1/(x-2)
X
f. y +2=7 (x - 5)
1
g. y + 2 = = (x - 5)
7
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h. y-2=7 (x − 2)
-
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Answer :

Lanuel

The equation of a line that passes through the given points (5, -2) and is

perpendicular to y = 7x - 8 is given by y + 2 = -1/7(x - 5).

What is a slope?

The slope of a line simply refers to the gradient of a line and it's typically used to describe both the ratio, direction and steepness of an equation of a straight line.

Mathematically, the standard form of the equation of a straight line is given by;

y = mx + c

Where:

  • x and y are the points.
  • m is the slope.
  • c is the intercept.

y = mx + c ≡  y = 7x - 8

m₂ = 7

For perpendicularity, we have:

m₁ × m₂ = -1

m₁ × 7 = -1

m₁ = -1/7.

Next, we would use the point-slope form to write the equation of this line:

y - y₁ = m(x - x₁)

y - (-2) = -1/7(x - 5)

y + 2 = -1/7(x - 5).

Read more on slope here: brainly.com/question/1884491

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