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The velocity, V, of a specific object being dropped from a particular height, h, can be found by the radical function V - /2/a where a
represents the acceleration in At/sec?. If the acceleration due to gravity is 32.2 fu/sec?, at what height should you drop an object in order for it to
have a velocity of 80 ft/sec?
O
5,152 feet
O
99.4 feet
O
71.8 feet
0 d
1.5 feet



Answer :

ogorwyne

The height that the object would have to be dropped so that it would have a velocity of 80 would be 99.4 feet

How to solve for the velocity

You have the following available data to solve it with

V=80 ft/sec

Then you have

a = 32.2 ft/sec^2

The formula to find velocity is given as

V = [tex]\sqrt{2ha}[/tex]

But here we were not givben the value for h

such that

80 = √2 * 32.2 * h

80 = √64.4h

square both sides

80 ² = √64.4h²

6400 = 64,4h

Then we would have to divide through by 64.4

6400 / 64.4 = 99.4 feet

Hence we have to conclude that the height that you should have to drop the object so that it can have the velocity of 80 seconds is 99. 4 feet.

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